(4x^2+19x+13)/(x+4)

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Solution for (4x^2+19x+13)/(x+4) equation:


D( x )

x+4 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x in (-oo:-4) U (-4:+oo)

(4*x^2+19*x+13)/(x+4) = 0

4*x^2+19*x+13 = 0

4*x^2+19*x+13 = 0

DELTA = 19^2-(4*4*13)

DELTA = 153

DELTA > 0

x = (153^(1/2)-19)/(2*4) or x = (-153^(1/2)-19)/(2*4)

x = (3*17^(1/2)-19)/8 or x = (-3*17^(1/2)-19)/8

(x-((-3*17^(1/2)-19)/8))*(x-((3*17^(1/2)-19)/8)) = 0

((x-((-3*17^(1/2)-19)/8))*(x-((3*17^(1/2)-19)/8)))/(x+4) = 0

( x-((-3*17^(1/2)-19)/8) )

x-((-3*17^(1/2)-19)/8) = 0 // + (-3*17^(1/2)-19)/8

x = (-3*17^(1/2)-19)/8

( x-((3*17^(1/2)-19)/8) )

x-((3*17^(1/2)-19)/8) = 0 // + (3*17^(1/2)-19)/8

x = (3*17^(1/2)-19)/8

x in { (-3*17^(1/2)-19)/8, (3*17^(1/2)-19)/8 }

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